We want to find two consecutive odd numbers, n1,n2 say, whose sum is 176. Let n1 = n −1 and n2 = n+ 1 for n ∈ Z. Then n1 +n2 = (n+ 1)+ (n− 1) = 2n = 176, so n = 176 2 = 88 and n1 = 87,n2 = 89. Answer link.
Dec 12, 2016 · The three integers are 11, 13, and 15. We shall consider the integers as x, (x+2), and (x+4). The sum of these is 39, so we can write: x+(x+2)+(x+4)=39 Open the brackets and simplify. x+x+2+x+4=39 3x+6=39 Subtract 6 from each side. 3x=33 Divide both sides by 3. x=11 Therefore: (x+2)=13 and (x+4)=15
find two consecutive odd integers whose sum iis 176,also find three consecutive integers whose sum is -93
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Solution for Find two consecutive odd positive integers , sum of whose squares is290
Consecutive Even Integers: A set of consecutive integers may be expressed by a single variable because the numbers may be related by the same variable using an appropriate expression.
Oct 20, 2009 · 2) Find 2 consecutive integers, the sum of whose squares is 143 more than twice their sum. 3) The sum of 2 numbers is 6. The sum of their squares is 180. What are the 2 numbers? 4) The sum of two numbers is 2. The sum of their squares is 49 more than their product. What are the two numbers?